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Find the smallest number of five digits exactly divisible by 16,24,36 and 54.

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Smallest number of five digits is 10000. 

Required number must be divisible by L.C.M. of 16,24,36,54 i.e 432,  

On dividing 10000 by 432,we get 64 as remainder. 

Required number = 10000 +( 432 – 64 ) = 10368.

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