Question

Simplification of the Boolean expression (A + B)’(C + D + E)’ + (A + B)’ yields which of the following results?

(a)  A + B)

(b)   A’B’

(c)  C + D + E

(d)  C’D’E’

(e)  A’B’C’D’E

Answer 1

(A + B)'(C + D + E)' + (A + B)'=(A+B)’((C+D+E)+1) (Distb. Law)

=(A+B)’.1 (Identity Law)

=(A+B)’ (Identity Law)

=A’B’ (DeMorgan’s Law)

So, simplification of the Boolean expression (A + B)’(C + D + E)’ + (A + B)’ yields