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Show that: ∫((2x + 4)/(x^2 − 4x + 8))dx for x ∈ [2, 4] = ln 2 + π

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 Show that:

∫((2x + 4)/(x2 − 4x + 8))dx for x ∈ [2, 4] = ln 2 + π

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= ln [(x − 2)2 + 4]42 + (8/2) tan−11

= ln 2 + π

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