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A and B can do a piece of work in 18 and 24 days respectively. They worked together for 8 days and then A left. The remaining work was finished by B in: 

(a) 5 days 

(b) 16/3 days 

(c) 8 days 

(d) 10 days 

2 Answers

+1 vote
by (71.8k points)
selected by
 
Best answer

Correct option (b) 16/3 days

Explanation: 

Description: Again, we will take T.W as L.C.M. of no. of days taken by A and B and we will calculate unit/day work by A and B) 

If A and B worked for 8 days so they will 

complete (4+3)×8= 7×8=56 units of work 

Work left = T.W – work completed 72-56=16 units 

Now 16 units will be done by B (3 units/day)

+1 vote
by (40.4k points)

we can determine the individual rates of work for A and B and calculate how much work they completed together in 8 days. Then, we can subtract that work from the total work to find the remaining work that B completed on their own.

Let's denote the total work as W.

A's rate of work: 1 work / 18 days
B's rate of work: 1 work / 24 days

Together, their combined rate of work is (1/18 + 1/24) works per day.

In 8 days, the amount of work they completed together is:
Work completed together = (1/18 + 1/24) * 8 = 8/18 + 8/24 = 4/9 + 1/3 = 12/27 + 9/27 = 21/27 = 7/9

The remaining work can be calculated as:
Remaining work = Total work - Work completed together = 1 - 7/9 = 2/9

B's rate of work is 1 work per 24 days, so to complete 2/9 of the work, B will take:
Time taken by B = (2/9) / (1/24) = (2/9) * (24/1) = 16/3 =  \(5\frac{1}{3}\)​​​​ days 

Therefore, B will take approximately 16/3 days to complete the remaining work on their own.

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