Correct option: (A) (D)
Explanation:
The given equations are
4x – 4y – z + 11 = 0 ...(i)
x + 2y – z – 1 = 0 ...(ii)
The DR's of normal to the planes (i) and (ii) are 4, –4, –1 and 1, 2, –1 respectively.
Let DR's of line of intersection of plane be l, m, n
As the line of intersection of the planes is perpendicular to the normals of the both planes, we get
4l – 4m – n = 0 and l + 2m – n = 0
By cross multiplication
If x = 0, Eqs. (i) and (ii) becomes
– 4y – z + 11 = 0
⇒ 2y – z – 1 = 0
Solving, we get
y = 2, z = 3
∴ Equation of line is
