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∫tan1/3 x dx    Take tanx = z ; sec2x dx = dz i.e dx = dz/(1+z2)

Putting t = 0, in the above, 

B+D = 0 ............ (1)

Putting t = 1, 

A + 2C + D = 1 ........... (2)

Putting t = -1,A + 2C-D = 1 ............ (3)

Using (2) & (3), D = 0

Therefore, B = 0 using (1)

A + 2C = 1 ................. (4)

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