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Consider Fraunhofer diffraction pattern obtained with a single slit illuminated at normal incidence. At the angular position of the first diffraction minimum, the phase difference (in radian) between the wavelets from the opposite edges of the slit is

(a)  π/4

(b)  π/2

(c)  2π

(d)  π

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Best answer

Correct option   (c)  2π

Explanation:

The figure depicts Fraunhofer diffraction pattern. For P to be first minimum, the phase difference between OA or OB is π .

 

∴ Phase difference from opposite edges = 2π radian 

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