Question

A particle is projected vertically upwards with velocity 40 m/s. Find the displacement and distance travelled by the particle in

(a) 2s 

(b) 4s 

(c) 6s 

[Take g = 10 m/s ² ]

Answer 1

Here, u is positive (upwards) and a is negative (downwards). So, first we will find t₀ , the time when velocity becomes zero.

(a) t < t₀ . Therefore, distance and displacement are equal. 

(b) t = t₀ . So, again distance and displacement are equal.

(c) t > t₀ . Hence, d > s