The energy required to force an α-particle(classically) into a nucleus of charge Ze is equal to the potential energy at the barrier height and is given by
E = zZe2/4πε0R.
This is barely possible when α particle and the Uranium nucleus will just touch each other and the kinetic energy of the bombarding particle is entirely converted into potential energy.
R = R1 + R2 = r(A1/31 + A21/3)
= 1.2(41/3 + 2381/3) = 9.34fm
E = 1.44zZ/R = 1.44 × 2 × 92/9.34 = 28.37MeV