Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
38.7k views
in Physics by (71.2k points)

A string under a tension of 129.6 N produces 10 beats/ s when it is vibrated along with a tuning fork. When the tension in the string is increased to 160 N, it sounds in unision with the same tuning fork. Calculate the fundamental frequency of the tuning fork.

1 Answer

+2 votes
by (63.7k points)
selected by
 
Best answer

Suppose f be the frequency of the tuning fork. The frequency of the string will be either (f – 10) or (f + 10). With the increase in tension its frequency becomes f, so initial frequency of the string is (f – 10). Thus

After solving equations (i) and (ii), we get 

f = 100 Hz

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...