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One pound-mass of diatomic oxygen (O2 molecular weight 32) is contained in a 100-gal tank. Find the specific volume on both a mass and mole basis (v and v ). 

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V = 231 in3 = (231 / 123) ft3 = 0.1337 ft3

This is based on the definition of the specific volume

v = V/m = 0.1337 ft3/1 lbm = 0.1337 ft3/lbm 

v¯ = V/n = V/m/M = Mv = 32 × 0.1337

= 4.278 ft3/lbmol

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