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Two sitar strings A and B playing the note ‘Ga’ are slightly out of tune and produce beats of frequency 6 Hz.

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Two sitar strings A and B playing the note ‘Ga’ are slightly out of tune and produce beats of frequency 6 Hz. The tension in the string A is slightly reduced and the beat frequency is found to reduce to 3 Hz. If the original frequency of A is 324 Hz, what is the frequency of B ?

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Given, fA = 324 Hz. 

The frequency fB = 324 ± 6 

= 330 Hz. 

or = 318 Hz. 

When string A is waxed, its frequency will decrease and may give 3 beats for the frequency 318 Hz. Thus 

fB = 318 Hz.

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