Correct option (b) 0.81 J
Explanation:
Since, 2 μF and 3 μF capacitors are in parallel.
So, their effective capacitance is
C′ = 2 + 3 = 5 μF
Now 12 μF, 20 μF and C′ are in series.
Therefore, their effective capacitance is
The charge at C′, 20 μF and 12 μF capacitors is equal
Hence, potential difference across 2 μF capacitor
So, energy stored in 2 μF capacitor will be