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in Physics by (69.3k points)

The surface tension of water is 0.073 Nm–1 . 8 drops of water, each of radius 1 mm,merge to form a single drop. Determine the change in internal energy of the drops.

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Surface energy lost due to merging goes into the form of change in internal energy.

Surface energy be foce the merging = 8 × 4π (1 mm)2 × 0.073 (Nm–1 ).

The eight drops merge to forma single drop.

r = 2 mm

New surface area = 4π (2mm)2 .

Surface energy after the merger

= 4π (2mm)2 × 0.073 Nm–1

Lost surface energy

The change in internal energy is, thus, 3.67 × 10–3 J

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