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in Mathematics by (70.0k points)

The equation of the circle which touches the axes of the co-ordinates and the line x/3 +y/4 = 1 and whose centre lies in the first-quadrant is

x2 + y2 − 2cx − 2cy + c2 = 0, where c is : 

(a) 1, 6 

(b) 4, 5 

(c) 3, 4 

(d) 2, 3

1 Answer

+1 vote
by (71.8k points)
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Best answer

Correct option (a) 1, 6

Explanation:

The equation of the circle touching the co-ordinate axes is

Perpendicular distance between circle (c, c) and line is

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