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in Physics by (67.9k points)

A hydraulic hoist raises a 3650 lbm car 6 ft in an auto repair shop. The hydraulic pump has a constant pressure of 100 lbf/in.2 on its piston. What is the increase in potential energy of the car and how much volume should the pump displace to deliver that amount of work?

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C.V. Car.

No change in kinetic or internal energy of the car, neglect hoist mass.

E2 – E1 = PE2 - PE1 = mg (Z2 – Z1)

= 3650 x 32.174 x 6/32.174

 = 21900 lbf-ft

The increase in potential energy is work into car from pump at constant P.

W = E2 – E1 = ∫P dV = P ∆V 

⇒ ∆V = E2 – E1/P = 21900/100 × 144

= 1.52 ft3

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