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A particle of mass m moves in a one-dimensional potential energy U(x) = –ax^2 + bx^4 ,

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A particle of mass m moves in a one-dimensional potential energy U(x) = –ax2 + bx4 , where a and b are positive constants. The angular frequency of small oscillations about the minim a of the potential energy is equal to

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Best answer

Correct option: (B)

Explanation:

U = –ax2 + bx4 

At mean position F = 0

ma´ = + 4ax

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