Answer: h ≅ 57m; t = 3.4sec.
Explanation:
The equations for the length of paths AC and AB (Fig.) 194 travelled by the body from the beginning of the fall are
AC = h = 1/2(gt2) and AB = 1/2(h) = 1/2g(t - 1)2,
where t is the time of fall from A to C. The solution of these equations gives the values of t and h.
Alternative solution: We consider the equations for the two paths AB and BC. The equation for AB is
