Question

A stone sliding over a horizontal icy surface comes to rest in a distance of 48 m. Determine its initial velocity if the force of sliding friction between the stone and the ice is 0.06 times the weight of the stone. 

Answer 1

Answer: v₀ = 7.51m/sec.

Explanation:

If the weight of the stone is P — mg, then the force of friction is F = kP = kmg. The deceleration of the stone under the action of this force is determined from the equation kmg = ma; the initial velocity is obtained from the relation v₀ = √(2aS) = √(2kgS) = 7.51m/sec.