Question

A bar magnet has a length of 10 cm and a pole strength of 10 e.m.u. Determine the magnitude and direction of the field strength at a point A lying on the axis of the magnet at a distance of 5 cm from the south pole.

Answer 1

Explanation:

The field strength at point A is equal to the difference in strengths due to each of the poles, H = H₁ - H₂ = m/(a + l)² - m/a²,  where m, is the pole strength, l  is the length of the magnet, and a is the distance from the S pole.