Answer: m = 66 e. m. u.
Explanation:
The force of interaction between the neighbouring like poles is F1 = m2/a2; since a < l, the force of interaction between the like poles is approximately F2 = m3/4l2, and the force of interaction between the unlike poles F3 = m2/l2;

The forces F2 and F3 are negligibly small in comparison with F1, and therefore the field strengths can be determined with sufficient accuracy from force F1 . Setting F1 = P, we have
