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If sin-1 (2a/1+a2) + cos -1 (1- a2)/(1+a2) = tan-1 (2x)/(1-x2) where a, x ∈ ]0,1[, then the value of x is
(a) 0 
(b)a/2
(c) a 
(d)2a/1- a2

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