Question

Two batteries with e.m.f 12 V and 13 V are connected in parallel across a load resistor of 10 Ω. The internal resistances of the two batteries are 1 Ω and 2 Ω respectively. The voltage across the load lies between.
(1) 11.5 V and 11.6 V

(2) 11.4 V and 11.5 V

(3) 11.7 V and 11.8 V

(4) 11.6 V and 11.7 V

Answer 1

Ans. (1)

Now its equivalent circuit is :

i =(37/3)/(10 + 2/3) =37/32
 V_10Ω = i × 10 = 37/32*10 = 370/32 =11.56 volt
Hence (1)