A drop of liquid of radius R = 10^–2 m having surface tension S = 0.1/4π Nm^-1

A drop of liquid of radius R = 10^–2m having surface tension S = 0.1/4π Nm^-1divides itself into K identical drops In this process the total change in the surface energy ΔU = 10^–3 J. If K = 10^α then the value of α is

A drop of liquid of radius R = 10^–2 m having surface tension S = 0.1/4π Nm^-1

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