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If n ∈ N , then 121^n – 25^n + 1900^n – (–4)^n is divisible by which one of the following?

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in Mathematics by (45.8k points)

If n ∈ N , then 121n – 25n + 1900n – (–4)n is divisible by which one of the following? 

a. 1904 

b. 2000 

c. 2002 

d. 2006

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1 Answer

+1 vote
by (68.6k points)
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Best answer

Correct option b. 2000

Explanation:

Putting n = 1, 121n – 25n + 1900n – (–4)n

= 121 – 25 + 1900 + 4 = 2000

Which is divisible by 2000 

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