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 If the normal at the point t1 on the parabola y2 = 4ax meets it again at point t2 then prove that t1t2 + t12 + 2 = 0. 

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Equation of the parabola is y2 = 4ax 

Equation of normal at t1= (at12 ,2at1 ) is 

y+xt1 = 2at1+ at13

This normal meets the parabola again at (at22 ,2at2 ) . 

Therefore, 

 

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