
A ray of light along y = b intersects the parabola at p(b2/4a ,b)
Equation to the parabola is y2 = 4ax ....(1)
Differentiating (1) dy/dx = 2a/y
Slope of normal at P is - b/2a
If the angle between ray of light and the normal is θ then tan θ = b/2a
Let PQ be reflected ray
Angle between PQ and the normal at P is also θ
Let the slope of PQ be m


4abx + (5a2 – b2) y – 4a2 b = 0
Substitute S(a, 0)
Reflected ray passes through the focus.