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in Mathematics by (67.9k points)

Solve the differential equations d2y/dx2 + a2y = cosec ax

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The given equation in its symbolic form is (D2 + a2 )y = cosec ax 

Thus, the auxiliary equation becomes D2 + a2 = 0 i.e. D = ±ia

∴ C.F. = (c1cos ax + c2sin ax)

For P.I = 1/D2 + a2 cosec ax

= 1/D2 -(-a2) cos ec ax

= 1/(D + ia)(D - ia)cosec ax

= 1/2ia(1/D -ia - 1/D + ia) cosec ax(By partial Fractions)

On the same lines, changing i to –i, we get

1/D + ia cosec ax = e-iax[log(sin ax/a) + ix]

Using (1) and (2),

Hence the complete solution is

y = (c1 cos ax + c2 sin ax) + 1/a (log(sin ax)/a sin ax - x cos ax)

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