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If ∫ t/1 + t2 x∈[e-1, tanx] dt ∫ dt/t(1 + t2) x∈[e-1, costx]  dt =

(a)   1 

(b)   e 

(c)  e –1

(d) π/4

1 Answer

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Best answer

Correct option (a) 1

Explanation:

Put t = 1/Z   in 2nd integral

dt = - 1/z2  dz

2nd integral reduces to

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