Correct option (a) and (d)
Explanation:
α ,β = - b ± √Δ2/2a and β = - b - Δ/2a
or α = -b - Δ/2a and β = - b + Δ/2a
2aα = - b + Δ 2αβ = - b - Δ
2aα + Δ = – b & 2a β - Δ = -b
2aα + Δ = - b + 2Δ
2a β - Δ = -b - 2Δ
S = –2b and P = b2
∴ S = – 2b and P = + b2 – 4 Δ2
= + b2 – 4(b2 – 4ac)
= –3b2 + 16ac
∴ quadatic equation is
x2 + 2bx – 3b2 + 16ac = 0