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Σcos^2rπ/n r∈[r = 1, n - 1]

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Σcos2rπ/n  r∈[r = 1, n - 1]

(a)   n/2

(b)  n/2 - 1/2

(c)   n/2 - 1

(d)  None of these

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Correct option   (c)  n/2 - 1

Explanation:

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