Question

Calculate the normality of solution containing 3.15g of hydrated oxalic acid (H₂C₂O₄.2H₂O) in 250ml of solution (Mol. mass = 126). 

Answer 1

Mass of oxalic acid = 3.15g 

Equivalent mass of oxalic acid 

= Mol.mass / Basicity

= 126 / 2 = 63 g equiv^-1

Equivalents of oxalic acid

= Mass of solute / Eq.Mass

Volume of solution = 250ml 

= 250 / 1000 L =0.25L

Normality = Equivalent of Solute / Volume of solution inL

= 0.05 equiv / 0.25 L = 0.2N