It will be seen that there are two deltas in the circuit i.e. ABC and DEF. They have been converted into their equivalent stars as shown in Fig. . Each arm of the delta ABC has a resistance of 12 Ω and each arm of the equivalent star has a resistance of 4 Ω. Similarly, each arm of the delta DEF has a resistance of 30 Ω and the equivalent star has a resistance of 10 Ω per arm.
The total circuit resistance between A and F
= 4 + 48 || 24 + 10 = 30 Ω.
Hence I = 180/30 = 6 A.
Current through 10Ω resistor as given by current-divider rule
= 6 × 48/(48 + 24) = 4 A.
