Question

State Norton’s theorem and find current using Norton’s theorem through a load of 8 Ω in the circuit shown in Fig..

Answer 1

In Fig.  load impedance has replaced by a short-circuit. I_SC = I_N = 200/2 = 100A.

Norton’s resistance RN can be found by looking into the open terminals of Fig. . For this purpose Δ ABC has been replaced by its equivalent Star. As seen, RN is equal to 8/7 Ω. Hence, Norton’s equivalent circuit consists of a 100 A source having a parallel resistance of 8/7Ω as shown in Fig.. The load current IL can be found by using the Current Divider rule.

I_L = 100 x (8/7)/(8 + (8/7)) = 12.5A