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Show that three vectors a, b, c are coplanar iff vectors[a b c] = 0

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Suppose vector(a, b, c) are coplanar

If vector(a = 0), then vector(a*b = 0) and hence

Let vector{a ≠ 0}. If a, b are collinear (parallel) then vector{a*b = 0} and hence

Let vector{a,b} be non-collinear. Then vector c lies in the plane generated by vector{a,b} and hence vector c is perpendicular to vector{a*b}.

Thus 

Conversely suppose that 

If vector{a = 0 or b = 0 or c = 0, then a, b, c} are coplanar.

Let vector{a ≠ 0, b ≠ 0, c ≠ 0}.

If vector{a,b} are collinear (parallel), then vector{b = αa} for some scalar α. Since any two vectors are coplanar, vector{a,c} are coplanar

=> vector{αa, c} are coplanar 

=> vector{b, c} are coplanar 

=> vector{a, b, c} are coplanar.

Let vector{a, b} be non-collinear. Then vector{a*b ≠ 0}.

=> vector{a*b} is perpendicular to vector c

Since vector[a*b} is a vector perpendicular to the plane generated by vector{a, b} , it follows that vector c lies in the plane generated by vector{a, b} . Thus vector{a, b, c} are coplanar. 

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