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+1 vote
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in Mathematics by (66.2k points)

 If ω(≠ 1) is a cube root of unity and (1 +ω)7 = A + Bω,then A and B are respectively

(A) 0, 1 

(B) 1, 1 

(C) 1, 0 

(D) – 1, 1

1 Answer

+2 votes
by (55.7k points)
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Best answer

Correct option (B) 1, 1

Explanation:

(1 + ω)7 = (1 + ω) (1 + ω)6

= (1 + ω) (–ω2)6

= 1 + ω

⇒ A + Bω = 1 + 0 

⇒  A = 1, B = 1

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