Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
56.3k views
in Physics by (65.7k points)
recategorized by

Convert the following reading of pressure to kPa, assuming that the barometer reads 760mm Hg.

(1) 90cm Hg gauge (2) 40cm Hg vacuum (3) 1.2m H2O gauge

1 Answer

+2 votes
by (19.2k points)
selected by
 
Best answer

Given that h = 760mm of Hg for Patm 

Patm = ρgh = 13.6 × 103 × 9.81 × 760/1000 = 101396.16

 N/m2 = 101396.16Pa = 101.39KPa                                                              ...(i)                                                       

(a) 90cm Hg gauge 

Pgauge = ρgh = 13.6 × 103 × 9.81 × 90/100 = 120.07KPa                             ...(ii)

Pabs = Patm + Pgauge  = 101.39 + 120.07 

Pabs = 221.46KPa .......ANS

 (b) 40cm Hg vacuum

 Pvacc = ρgh = 13.6 × 103 × 9.81 × 40/100 = 53.366KPa                              ...(iii)

Pabs = Patm – Pvacc 

= 101.39 – 53.366

 Pabs = 48.02KPa .......ANS

 (c)1.2m Water gauge

 Pgauge = ρgh = 1000 × 9.81 × 1.2 = 11.772KPa                                          ...(iv)

Pabs = Patm + Pgauge

 = 101.39 + 11.772

 Pabs = 113.162KPa .......ANS

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...