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Given two current i1 = 10 sin (ωt + π/4) and i2 = 5 cos (ω t − π/2), find the r.m.s. value of i1 + i2 using the complex number representation. 

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The maximum value of first current is 10 A and it leads the reference quantity by 45°. The second current can be written as

i2 = 5 cos (ωt − π/2) = 5sin [90 + (ωt − π/2)] = 5 sin ωt

Hence, its maximum value is 5 A and is in phase with the reference quantity.

∴ Im1 = 10 (cos 45° + j sin 45°) = (7.07 + j 7.07)

Im2 = 5 (cos0° + j sin0°) = (5 + j0)

The maximum value of resultant current is

Im = (7.07 + j7.07) + (5 + j0) = 12.07 + j7.07 = 14 ∠ 30.4°

∴ R.M.S. value = 14/√2 = 10 A

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