Question

Draw admittance triangle between the terminals AB of Fig labelling its sides with appropriate values and units in case of : 

(i) X_L = 4 and X_C = 8 (ii) X_L = 10 and X_C = 5

Answer 1

(i) X_L = 4 Ω, X_C = 8 Ω

(i) Admittance triangle for first case

Z_CB = (jX_L(-jX_C))/(j(X_L - X_C) = j8

Z_AB = 1 + j 8 ohms 

Y_AB = 1/Z_AB = (1/65) −j (8/65) mho 

(ii) X_L = 10 Ω, XC = 5 Ω

Z_CB = (j10 x (- j5))/j5 = - j10

Z_AB = 1 −j 10 ohms 

Y_AB = (1/101) + j (10/101) mho