Given that vector a, vector b and vector c are mutually perpendicular vectors
∴ vector(a x b) = vector(b x c) = vector (c x a) = 0
It is also given that |vector a| = |vector b| = |vector c|
Let vector vector(a + b + c) be inclined to vector a, vector b and vector c at angles α, β and γ respectively

Now as |vector a| = |vector b| = |vector c|, therefore, cosα = cosβ = cosγ
∴ α = β = γ
Hence, the vector(a + b + c) is s equally inclined to vector a, vector b and vector c.