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The dissolution of Al(OH)3 by a solution of NaOH results in the formation of: (A) [Al(H2O)4 (OH)]^2+

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The dissolution of Al(OH)3 by a solution of NaOH results in the formation of: 

(A) [Al(H2O)4 (OH)]2+ 

(B) [Al(H2O)2 (OH)4] - 

(C) [Al(H2O)3 (OH)3] 

(D) [Al(H2O)6 (OH)3]

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(B) [Al(H2O)2 (OH)4] - 

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