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What is the relation between two specific heat ?

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dQ = dU + dW; for a perfect gas 

dQ at constant pressure 

dU at Constant volume; = mCvdT = mCv(T2 – T1

dW at constant pressure = PdV = P(V2 – V1) = mR(T2 – T1

Putting all the values we get

dQ = mCv(T2 – T1) + mR(T2 – T1)

dQ = m(CV + R)(T2 – T1)

but dQ = mCp(T2 – T1)

mCp(T2 – T1) = m(CV + R)(T2 – T1)

Cp = CV + R; Cp - CV = R ...(i)

Now divided by Cv; we get

Cp /CV – 1 = R/Cv; Since Cp /CV = y (gama = 1.41)

y – 1 = R/Cv;

or Cv = R/ (y – 1); CP = yR/ (y – 1); CP>CV; y>1

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