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Position vectors of A and B are 2i + 2j + k and 2i + 4j + 4k. Length of internal bisector of ∠BOA of ∆AOB is

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Position vectors of A and B are 2i + 2j + k and 2i + 4j + 4k. Length of internal bisector of ∠BOA of ∆AOB is

(A) √(136/9)

(B) √(- 136/9)

(C) 20/3

(D) None of these

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1 Answer

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Best answer

Correct option (A) √(136/9)

Explanation:

 Let M be the point of intersection of internal bisector with AB.

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