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in Physics by (66.2k points)

A beam 8m long is hinged at A and supported on rollers over a smooth surface inclined at 300 to the horizontal at B. The beam is loaded as shown in fig. Determine the support reaction.

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F.B.D. is as shown in fig,

∑H = 0

RAH ⋅ + 8 cos 45° – RBsin 30° = 0 

0.5RB – RAH ⋅ = 5.66 ...(i) 

∑V = 0

RAV –10 – 8 cos 45° – 10 + RB cos 30° = 0

RAV + 0.866 RB = 25.66

Taking moment about point A:

∑MA = 10 × 2 + 8 cos 45° × 4 + 10 × 7 – RB cos 30° × 8= 0

RB = 16.3KN

From equation (ii)

RAV = 11.5KN

From equation (1)

RAH = 2.5KN.

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