The correct answer is (c) -5 J/kg
EXPLANATION:
Work done by the person = -3 J (Given) Work done in increasing the velocity from rest to 2 km/s = K.E. of the mass at A =½mv² = ½*1*2² = 2 J Let the potential at A be X J/kg,
So, the change in P.E. of the mass = the work done in slowly bringing the mass from infinity to A = mX
= 1*X = X J
So the total work done = Change in P.E + Change in K.E. = X+2 J, but it is given -3 J so, X+2 = -3
→X = -3-2 = -5 J