Question

The point of intersection of the lines whose parametric equations are x = 3r + 3, y = − 4r + 2, z = r − 1 and x = − 6t + 1, y = 3t − 2 and z = 1 is 

(A) (9, 6, −1) 

(B) (9, −6, 1) 

(C) (−9, 6, −1) 

(D) (9, 6, 1)

Answer 1

Correct option is (B) (9, − 6, 1)

Answer 2

there is one shortcut too...substitute r = 2 ...then first equation will become x = 9 ,  y = -6 , z = 1 respectively....and thus the answer