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Let f:(– 1, 1)  B be a function is defined by f(x) = tan-1(2x/(1 - x2)), then f is one-one and onto, when B is the interval

(a) [0, π/2)

(b) (0, π/2)

(c) (-π/2, π/2)

(d) [- π/2, π/2]

1 Answer

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Best answer

Correct option (c) (-π/2, π/2)

Explanation:

The range of the function f is (-π/2, π/2)

Since the function f is onto, so Rf = Cf = B

Thus, B = (-π/2, π/2)

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