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Let cos-1(x) + cos-1(2x) + cos-1(3x) = π If x satisfies the cubic equation ax3 + bx2 + cx + d = 0, then find the value of (b + c) - (a + d)

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Given, cos-1(x) + cos-1(2x) + cos-1(3x) = π

Thus, a = 12, b = 14, c = 0, d = - 1

Hence, the value of (b + c) - (a + d)

= 14 - 11 = 3.

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