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Evaluate: lim (x→0) ((1 – cos x cos2x cos3x)/sin^22x)

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Evaluate: lim (x→0) ((1 – cos x cos2x cos3x)/sin22x)

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1 Answer

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Best answer

We have cos x cos2x cos 3x

= 1/2(2 cos 3x cos x) cos2x

= 1/2(cos 4x + cos 2x) cos2x

= 1/4(2 cos 4x cos2x + 2cos22x)

= 1/4(cos 6x + cos2x + 1 + cos 4x)

= 1/4(1 + cos 2x + cos4x + cos6x)

Thus

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