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If f(x) = {(sinx, x ≠ nπ, n ∈ z), (2, otherwise) and g(x) = {(x^2 + 1, x ≠ 0, 2), (4, x = 0), (5, x = 2)

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If f(x) = {(sinx, x ≠ nπ, n ∈ z), (2, otherwise) and g(x) = {(x2 + 1, x ≠ 0, 2), (4, x = 0), (5, x = 2) then lim(x→0) (g(f(x))) is... 

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Limit = lim(x→0)(g(f(x)))

= lim(x→0)(g(sinx))

= lim(x→0)((sinx)2 + 1)

= 1

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